a2zinterviews

11.	A person has to cover a distance of 6 km in 45 minutes. If he covers one-half of the distance in two-thirds of the total time; to cover the remaining distance in the remaining time, his speed(in Km/hr) must be
	A.  6
	B.  8
	C.  12
	D.  15

Solution

Remaining distance = 3 km/hr Remaining time = (1/3 x 45) min = 15 min = 1/4 Required speed = (3 x 4) km/hr = 12 km/hr.

12.	A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips?
	A.  36 kmph
	B.  45 kmph
	C.  48 kmph
	D.  50 kmph

Solution

Speed on return trip=150% of 40 = 60 kmph. Average speed =(2 x 40 x 60/40+60)km/hr = (4800/100)km/hr = 48 km/hr.

13.	A car moves at the speed of 80 km/hr. what is the speed of the car in metres per second?
	A.  8 m/sec
	B.  20x1/9 m/sec
	C.  21x2/9 m/sec
	D.  22x2/9 m/sec

Solution

Speed = (80 x 5/18) m/sec = 200/9 m/sec = 22x2/9 m/sec.s

14.	A and B walk a circulat track. They start at 8 a.m from the same point in the opposite directions. A and B walk at a speed 0f 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m?
	A.  5
	B.  7
	C.  9
	D.  11

Solution

Relative speed = (2+3) = 5 rounds per hour. So, they cross each other 5 times in an hour and 2 times in half an hour. Hence, they cross each other 7 times before 9.30 a.m.

15.	The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
	A.  10 a.m
	B.  10.30 a.m
	C.  11 a.m
	D.  11.30 a.m

Solution

Suppose they meet x hrs after 8 a.m. then (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330. Therefore 60x+75(x-1) <=> 330. x=3. So,they meet at (8+3). i.e 11a.m.