DIRECTIONS : Problems based on Average.
28. |
The average of 50 numbers is 30. If two numbers, 35 and 40 are discarded, then the average of the remaining numbers is nearly |
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A. 28.32 |
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B. 28.78 |
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C. 29.27 |
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D. 29.68 |
Solution |
Sum of 50 numbers |
= 30 x 50 |
= 1500. |
Sum of remaining 48 numbers |
= 1500 - (35+40) |
= 1425. |
∴ Required average |
= (1425 / 48) |
= 475 / 16. |
= 29.68. |
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29. |
The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is |
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A. 35.2 |
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B. 36.1 |
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C. 36.2 |
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D. 36.5 |
Solution |
Correct sum | = (36x50+48-23)
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= 1825. |
∴ Correct mean | = 1825 / 50
|
= 36.5. |
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30. |
The average age of the mother and her six children is 12 years which is reduced by 5 years if the age of the mother is excluded. How old is the mother? |
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A. 40 years |
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B. 42 years |
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C. 50 years |
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D. 52 years |
Solution |
Age of the mother | = (12 x 7 - 7 x 6) |
= 42 years. |
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