a2zinterviews

11.	Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together.
	A.   10x11/10
	B.   10x10/11
	C.   11x10/11
	D.   12x10/11

Solution

At 8 o'clock, the hour is at 8 and the minute hand is at 12,i.e. the two hands are 20 min. Spaces apart. So, the minute hand gain = (30 - 20)minute 55 minutes will be gained in 60 min. 10 minutes spaces will be gained in (60/55 x10) min. = 10x10/11 min. The hands will be in the same straight line but not together at 10x10/11 min.past 8.

12.	The angle between the minute hand and the hour hand of a clock when the time is 4.20, is
	A.  0°
	B.  5°
	C.  10°
	D.  20°

Solution

Angle traced by hour hand in13/3 hrs = (360/12 x 13/3)° =130° Angle traced by min. hand in 20 min = (360/60x20)° = 120° Required angle = (130 - 120)° = 10°.

13.	At 3.40, the hour hand and the minute hand of a clock form an angle of
	A.  120°
	B.  125°
	C.  130°
	D.  135°

Solution

Angle traced by hour hand in 12 hrs. = 360° Angle traced by it in 11/3 hrs. = (360/12x11/3)° = 110° Angle traced by minute hand in 60 min. = 360° Angle traced by it in 40 min. = (360/60x40)° Therefore ,Required angle(240-110)° = 130°

14.	The angle between the minute hand and the hour hand of a clock when the time is 8.30, is
	A.  80°
	B.  75°
	C.  60°
	D.  105°

Solution

Angle traced by hour hand in 17/2 hrs = (360/12x17/2 )° = 255. Angle traced by min hand in 30 min = (360/60x30)° = 180. Required angle = (255 - 180)° =75°.

15.	At what angle the hands of a clock are inclined at 15 minutes past 5?
	A.  58 ½°
	B.   64°
	C.   67 ½°
	D.   72 ½°

Solution

Angle traced by hour hand in 21/4 hrs. = (360/12x21/4)° = 157½° Angle traced by min.hand in 15 min = (360/60x15)° = 90° Therefore, the Required angle = [(157½°)-90°] = 67½°