Arithmatical - Compound Interest
DIRECTIONS : Problems based on Interest.
9. |
If the simple interest on a sum of money at 5% per annum for 3 years is Rs.1200, find the compound interest on the same sum for the same period at the same rate. |
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A. 1251 |
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B. 1261 |
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C. 1271 |
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D. 1281 |
Solution |
Clearly, Rate | = 5% p.a. |
Time | = 3 years |
S.I | =Rs.1200. |
So,Principal | =Rs.(100 x 1200/3x5) |
=Rs.8000. |
Amount | =Rs.[8000 x (1+5/100)³] |
=Rs(8000x21/20x21/20x21/20) |
= Rs.9261 |
C.I | =Rs.(9261-8000) |
=Rs.1261. |
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10. |
What will be the compound interest on a sum of Rs.25,000 after 3 years at the rate of 12 p.c.p.a? |
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A. Rs.9000.30 |
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B. Rs. 9720 |
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C. Rs. 10123.20 |
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D. Rs. 10483.20 |
Solution |
Amount | = Rs.(25000x(1+12/100)³ |
=Rs.(25000x28/25x28/25x28/25) |
= Rs. 35123.20. |
C.I | =Rs(35123.20-25000) |
=Rs.10123.20. |
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11. |
The compound interest on Rs.30,000 at 7% per annum is Rs.4347. The period (in years) is |
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A. 2 |
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B. 2½ |
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C. 3 |
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D. 4 |
Solution |
Amount | =Rs(30000 + 4347) |
= Rs.34347. |
Let the time be n years. |
Then, 30000(1+7/100)^n |
= 34347. |
=34347/3000 |
=11449/1000 |
=(107/100)^n |
n= 2years. |
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12. |
The present worth of Rs.169 due in 2 years at 4% per annum compound interest is |
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A. Rs.150.50 |
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B. Rs.154.75 |
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C. Rs.156.25 |
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D. Rs.158 |
Solution |
Present Worth | = Rs.[169/(1+4/100)²] |
= Rs.(169x25/26x25/26) |
= Rs.156.25 |
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