Arithmatical - Permutations and Combinations
DIRECTIONS : Problems based on Permutations.
16. |
How many arrangements can be mado out of the letters of the word 'ENGINEERING' ? |
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A. 277200 |
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B. 92400 |
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C. 69300 |
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D. 23100 |
Solution |
The word 'ENGINEERING' contains 11 letters, namely 3E, 3N, 2G, 2I and 1R. |
Required number of arrangements | = 11 ! / (3!)(3!)(2!)(2!)(1!) |
‹=› 277200. |
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17. |
Evaluate : 30! / 28! |
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A. 550 |
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B. 610 |
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C. 870 |
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D. 920 |
Solution |
We have 30! / 28! | = 30 x 29 x (28!) / 28! |
= (30 x 29) |
= 870. |
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18. |
In how many different ways can the letters of the word ‘Banking’ be arranged so that the vowels always come together? |
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A. 240 |
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B. 360 |
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C. 480 |
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D. 720 |
Solution |
In the word ‘Banking’, we treat the two vowels AI as one letter. Thus, we have BNKNG (AI). |
This has 6 letters of which N occurs 2 times and the rest are different. |
Number of ways of arranging these letters | = 6! / (2!)(1!)(1!)(1!)(1!) |
‹=›360. |
Now, 2 vowels AI can be arranged in 2! | = 2 ways. |
Required number of ways | = (360 x 2) |
‹=› 720. |
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19. |
Find the value of 4P4 |
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A. 12 |
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B. 14 |
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C. 16 |
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D. 24 |
Solution |
4P4 | = 4! |
= (4 x 3 x 2 x 1) |
= 24. |
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20. |
Find the value of 50C50 |
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A. 0 |
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B. 1 |
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C. 2 |
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D. 3 |
Solution |
50C50 | = 1. |
Therefore nCn | = 1. |
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