Arithmatical - Simple Interest
DIRECTIONS : Problems based on Simple Interest.
13. |
A person takes a loan of Rs. 200 at 5% simple interest. He returns Rs. 100 at the end of 1 year. In order to clear his dues at the end of 2 years, he would pay |
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A. Rs.105 |
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B. Rs.110 |
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C. Rs.115 |
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D. Rs.115.50 |
Solution |
Amount to be paid | = Rs.(100+200x5x1/100 + 100x5x1/100) |
‹=›Rs. 115. |
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14. |
At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years? |
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A. 2% |
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B. 4% |
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C. 6% |
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D. 11% |
Solution |
Let sum = x |
Time | = 10 years. |
Then, S.I | = 2x /5, |
Rate | =(100 ×2x / x×5×10)% |
‹=›4%. |
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15. |
The simple interest on Rs. 1820 from march 9, 2003 to may 21, 2003 at 7x1/2% rate will be |
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A. Rs.22.50 |
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B. Rs.27.30 |
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C. Rs.28.80 |
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D. Rs.29 |
Solution |
Time | = (22+30+21) days |
‹=›73 days. |
‹=› 1/5 year. |
S.I | = Rs. (1820×15/2×1/5×1/100) |
‹=›Rs. 27.30. |
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16. |
At what percent per annum will a sum of money double in 16 years? |
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A. 6x1/4% |
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B. 5x3/2% |
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C. 7x2/3% |
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D. None of these |
Solution |
Let Principal | = P. |
Then,S.I = P and T = 16 yrs. |
Rate | = (100×P/P×16)% |
= 6×1/4%. |
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