Arithmatical - Problems on Trains
DIRECTIONS : Problems based on Trains.
21. |
Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively The ratio of their speeds is |
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A. 2 : 3 |
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B. 4 : 3 |
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C. 6 : 7 |
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D. 9 : 16 |
Solution |
Let us name the trains as A and B. | = (A'S speed) : (B's speed) |
=√b : √a |
= √16 : √9 |
= 4 : 3 |
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22. |
Two trains 100 meters and 120 meters long aer running in the same diredtion with speeds of 72 km/hr and 54 km/hr. In how much time will the first train cross the seconds? |
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A. 40 sec |
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B. 44 sec |
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C. 46 sec |
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D. 48 sec |
Solution |
Relative Speed of trains | = (72 - 54) km/hr |
= 18 km/hr |
= (18 x 5 /18) km/hr |
= 5 m /sec. |
Time taken to cover | = (100 + 120) m/sec |
= (220 / 5 ) sec |
= 44 sec |
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23. |
A train 220 m long is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going? |
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A. 12 sec |
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B. 15 sec |
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C. 16 sec |
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D. 18 sec |
Solution |
Speed of the train | = (59 + 7) kmph |
= (66 x 5 /18) m/sec |
= (55 / 3) m/sec. |
Time taken by it cover 220m at (55/3) m/sec | = (220 x 3/55) sec |
= 12 sec. |
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24. |
A train 360 m long is running at a speed of 45 km/hr. In what time it will it pass a bridge 140 m long? |
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A. 40 sec |
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B. 42 sec |
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C. 45 sec |
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D. 48 sec |
Solution |
speed | =(45 + 5 / 18)m/sec |
=(25 / 2)m/sec |
Total distance covered | =(360 + 140 )m |
=500 m |
Required time | =(500 x 2 / 25)sec |
= 40 sec. |
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25. |
A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a telegraph post, then the length of the train is |
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A. 90 m |
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B. 100 m |
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C. 120 m |
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D. 140 m |
Solution |
Speed | = (12 / 10 x 60)km/hr |
= (72 x 5/18) m/sec |
= 20 m/sec. |
Length of the train | = (speed x time ) |
= (20 x 6)m |
= 120 m.
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