a2zinterviews

11.	A train 280 m long, running with a speed of 63 km/hr will pass a tree in
	A.  15 sec.
	B.  16 sec.
	C.  18 sec.
	D.  20 sec.

Solution

Speed = (63 x 5/18) m/sec = 35/2 msec Time taken = (280 x 2 /35)m/sec = 16 sec.

12.	A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is ihe length of the train?
	A.  120 metres
	B.  180 metres
	C.  324 metres
	D.  None of these

Solution

Speed = (60 x 5/18) m/sec = (50 / 3) m/sec Length of the train = (speed x Time ) = (50/3 x 9) m = 150 m.

13.	A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
	A.  3.6 sec
	B.  18 sec
	C.  36 sec
	D.  72 sec

Solution

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr = (36 x 5/18) m/sec = 10 m/sec Distance covered = (240+120) m = 360 m Time taken = (360 / 10)sec = 36 sec.

14.	Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively Find the time taken by the slower train to pass the driver of the faster one.
	A.  12 sec
	B.  24 sec
	C.  48 sec
	D.  60 sec

Solution

Relative speed = (45 + 30 )km/hr = (75 x 5/18)m/sec =(125 / 6) m/sec Total Distance covered = (500 + 500) m = 1000 m Required time = (1000 x 6 /125)sec = 48 sec

15.	A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the Length of the other train?
	A.  230 m
	B.  240 m
	C.  260 m
	D.  320 m

Solution

Relative Speed = (120 + 80)km/hr = (200 x 5/18)m/sec = (500 / 9)m/sec Let the length of the other train be x metres Then, x + 270 / 9 x + 270 = 500 x = 230.