Arithmatical - Problems on Trains

DIRECTIONS : Problems based on Trains.
1. A train 100 m long is running at the speed of 30 km/hr. Find the time taken by it to pass a man standing near the railway line.
  A.  10 sec.
  B.  12 sec.
  C.  14 sec.
  D.  16 sec.
Solution
Speed of the train = (30 x 5/18)m/sec
= (25 / 3) m/sec.
Distance moved in passing
the standing man
= 100 m.
Required time taken= 100 /( 25 / 3)
=(100 x 3 / 25) sec
= 12 sec.
2. A man sitting in a train which is travelling at 50 kmph observes that a goods train, travelling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed?
  A.  52 kmph.
  B.  62 kmph.
  C.  72 kmph.
  D.  80 kmph.
Solution
Relative Speed = (280 / 9)m/sec
= (280/9 x 18/5)
= 112 kmph.
Speed of the train = (112 - 50)kmph
= 62 kmph.

3. A train 150 m long is running with a apecd of 68 kmph. In what time will it pass a man who is running at 8 kmph in the same direction in which the train is going?
  A.  6 sec.
  B.  7 sec.
  C.  9 sec.
  D.  11 sec.
Solution
Speed of the train relative to man =( 68 - 8 )
= 60 Kmph
= 60 x 5 / 18
=50/3 m/sec.
Time taken by it to cover 150 m at (50 /3)m/sec = (112 - 50)kmph
= (150 x 3/50)sec
= 9 sec.
4. A train moves with a speed of 108 kmph. Its speed in metres per second is
  A.  10.8
  B.  18
  C.  30
  D.  38.8
Solution
Speed = 108 Kmph
= (108 x 5/18)m/sec
= 30 m/sec.
5. Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. The length of the faster train is
  A.  80 m
  B.  100 m
  C.  120 m
  D.  180 m
Solution
Relative Speed = (36 + 45) km/hr
= (81 x 5/18) m/sec
= (45/2) m/sec
Length of the train = (45 / 2 x 8) m
= 180 m.
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