Arithmatical – Alligation or Mixture
DIRECTIONS : Important Facts and Formulae
15. |
How many kilograms of sugar costing Rs.9 per kg must be mixed with 27 kg of sugar costing Rs.7 per Kg so that there may be a gain of 10% by selling the mixture at Rs.9.24 per Kg? |
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A. 36 Kg |
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B. 42 Kg |
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C. 54 Kg |
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D. 63 Kg |
Solution |
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By the rule of alligation: |
C.P. of 1 kg sugar of 1st kind |
C.P. of 1 kg sugar of 2nd kind |
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Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3. |
Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.
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16. |
In what ratio must rice at Rs.9.30 per Kg be mixed with rice at Rs.10.80 per Kg so that the mixture be worth Rs.10 per Kg? |
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A. 8 : 7 |
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B. 7 : 8 |
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C. 8 : 9 |
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D. 9 : 8 |
Solution |
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By the rule of alligation: |
C.P. of 1 kg rice of 1st kind (in paise) |
C.P. of 1 kg rice of 2nd kind (in paise) |
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Required ratio = 80 : 70 = 8 : 7. |
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17. |
In what ratio must be a grocer mix two varities of tea worth Rs.60 a kg and Rs.65 a Kg so that by selling the mixture at Rs.68.20 a Kg he may gain 10%? |
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A. 3 : 4 |
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B. 3 : 2 |
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C. 3 : 5 |
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D. 4 : 5 |
Solution |
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S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10 % |
C.P. of 1 kg of the mixture = Rs. (100 / 110 x 68.20) = Rs. 62. |
By the rule of alligation: |
C.P. of 1 kg tea of 1st kind |
C.P. of 1 kg tea of 2nd kind |
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Required ratio = 3 : 2. |
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