Arithmatical - Time and Work
DIRECTIONS : Problems based on time and work.
11. |
Ronald and Elan are working on an assignment. Ronald takes 6 hours to type 32 pages on a computer, while Elan takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages? |
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A. 7 hours 30 minutes |
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B. 8 hours |
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C. 8 hours 15 minutes |
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D. 8 hours 25 minutes |
Solution |
Number of pages typed by ronald in 1 hour | = 32/6 |
= 16/3. |
Number of pages typed by elan in 1 hour | = 40/5 |
= 8. |
Number of pages typed by both in 1 hour | = (16/3+8) |
=40/3. |
Time taken by both to type 110 pages | = (110×3/40)hrs |
= 8×1/4hrs |
= 8 hrs 15 min. |
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12. |
A can finish a work in 18 days and B can do the same in half the time taken by A. Then working together, what part of the same work they can finish in a day? |
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A. 1/6 |
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B. 1/9 |
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C. 2/5 |
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D. 2/7 |
Solution |
A's 1 day's work | = 1/18 |
and B's 1 day's work | = 1/9 |
(A+B)'s 1 day's work | = (1/18+1/9) |
= 1/6 |
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13. |
P can complete a work in 12 days working 8 hours a day, Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day. In how many days can they complete the work? |
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A. 5x5/11 |
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B. 5x6/11 |
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C. 6x5/11 |
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D. 6x6/11 |
Solution |
P can complete the work in (12x 8) hrs | = 96 hrs. |
Q can complete the work in (8x 10) hrs | = 80 hrs. |
P's 1 hour's work | = 1/96 |
Q's 1 hrs work | = 1/80 |
(P+Q)'s 1 hour's work | = (1/96+1/80) |
= 11/480. |
So, both P and Q will finish the work in | =(480/11) hrs. |
Number of days of 8 hours each | =(480/11x1/8) hrs. |
= 60/11 days |
=5x5/11 days. |
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14. |
A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in |
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A. 1/24 day |
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B. 7/24 day |
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C. 3x3/7 days |
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D. 4 days |
Solution |
(A+B+C)'s 1 day's work | = (1/24+1/6+1/12)
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= 7/24. |
So, A,B and C together will complete the job in 24/7 |
= 3x3/7 days.
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15. |
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With the help of C, they did the job in 4 days only. Then, C alone can do the job in |
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A. 9x1/5 days |
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B. 9x2/5 days |
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C. 9x3/5 days |
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D. 10 days |
Solution |
(A+B+C)'s 1 day's work | = 1/4 |
A's 1 day's work | = 1/16 |
B's 1 day's work | = 1/12 |
C's 1 day's work | = 1/4-(1/16+1/12) |
= (1/4 - 7/48) |
= 5/48. |
So,C alone can do the work in 48/5 | =9x3/5 days.
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