DIRECTIONS : Problems based on Area.
24. |
A housing society has been allotted a square piece of land measuring 2550.25 sq.m. What is the side of the plot? |
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A. 50.25 m |
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B. 50.5 m |
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C. 50.65 m |
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D. 50.85 |
Solution |
Side = √2550.25 |
= √255025 / 100 |
= 505 / 10 |
= 50.5 m. |
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25. |
A park square in shape has a 3 metre wide road inside it running along its sides. The area occupied by the road is 1764 square metres. What is the perimeter along the outer edge of the road? |
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A. 576 metres |
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B. 589 metres |
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C. 600 metres |
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D. 700 metres |
Solution |
Let the length of the outer edges be x metres. Then, length of the inner edge = ( x - 6)m. |
∴ x2 - (x-6)2 = 1764
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‹=› x2-(x2-12x+36)= 1764 |
‹=›12x = 1800 |
‹=›x = 150. |
∴ Required perimeter = (4x)m |
‹=› (4 x 150)m = 600m. |
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26. |
A can go round a circular path 8 times in 40 minutes. If the diameter of the circle is increased to 10 times the original diameter, then the time required by A to go round the new path once, travelling at the same speed as before is |
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A. 20 min |
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B. 35 min |
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C. 50 min |
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D. 70 min |
Solution |
Let original diameter be d metres. Then, its circumference = (Πd)metres. |
Time taken to cover (8Πd)m = 40 min. |
New diameter = (10d)m. Then, its circumference = (Π x 10d)m. |
Time taken to go round it once |
‹=› [40 / 8Πd x 10Πd]m |
‹=›50 min. |
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