DIRECTIONS : Problems based on Area.
1. |
A rectangular parking space is marked out by painting three of its sides. If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet? |
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A. 46 |
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B. 81 |
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C. 126 |
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D. 252 litres |
Solution |
Clearly,we have l=9 and l+2b=37 |
Area | = (l x b) |
=(9 x 14) sq.ft |
= 126 sq.ft. |
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2. |
The length of a rectangulat plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres? |
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A. 40 |
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B. 50 |
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C. 200 |
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D. 120 |
Solution |
Let breadth = x metres |
Then, length = (x + 20)metres. |
Perimeter | = (5300 / 26.50) m |
= 200m |
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3. |
The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m.What is the area of the field? |
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A. 18750 sq.m |
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B. 37500 sq.m |
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C. 40000 sq.m |
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D. 48000 sq.m |
Solution |
So length =250 m; breadth=150m |
Area | = (250 x 150)m² |
= 37500 m² |
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4. |
The length of a rectangualr hll is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is |
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A. 15 m |
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B. 22.5 m |
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C. 25 m |
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D. 30 m |
Solution |
Let the length = xmetres. Then length = (x +5)metres. |
Then,x(x +5)= 750 |
= x² + 5x - 750= 0 |
(x+30)(x-25)= 0 |
x=25. |
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