Arithmatical - Problems on Ages
DIRECTIONS : Problems based on Ages.
10. |
Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of Rajeev? |
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A. 5 years |
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B. 10 years |
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C. 20 years |
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D. 25 years |
Solution |
Let Rajeev's present age be x years. Then |
Rajeev's age 15 years | = (x+15) years. |
Rajeev's age 5 years back | = (x-5) years. |
Therefore | ‹=› x+15=5(x-5) |
‹=› x+15= 5x-25 |
‹=› 4x=40 |
‹=› x=10. |
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11. |
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is |
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A. 14 years |
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B. 18 years |
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C. 20 years |
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D. 22 years |
Solution |
Let the son's present age be x years .Then, man's present age | = (x+24)years. |
Then | ‹=›(x+24)+2= 2(x+2) |
‹=›x+26=2x+4 |
x= 22. |
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12. |
Hitesh is 40 years old and Ronnie is 60 years old. How many years ago was the ratio of their ages 3 : 5? |
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A. 5 years |
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B. 10 years |
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C. 20 years |
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D. 37 years |
Solution |
Suppose, the ratio was 3 : 5, x years ago. |
Then, | 40 - x / 60 - x |
= 3 / 5. |
‹=›5(40-x)=3(60-x) |
‹=›2x= 20 |
‹=›x= 10. |
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