a2zinterviews

16.	The ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages.
	A.  14 years
	B.  17 years
	C.  24 years
	D.  29 years

Solution

Let the age of the younger person be x years. Then, age of the elder person = (x + 16) years. Therefore ‹=› 3 (x - 6) =(x + 16 - 6) ‹=› 3x-18 = x+10 ‹=› 2x = 28 x= 14 years.

17.	The present ages of three persons are in proportions 4 :7 :9. Eight years ago, the sum of their ages was 56. Find their present ages (in years)
	A.  8, 20, 28
	B.  16, 28, 36
	C.  20, 35, 45
	D.  None of these

Solution

Let their present ages be 4x,7x and 9x years respectively. Then, (4x-8)+(7x-8)+(9x-8) = 56 20x = 80 x= 4. Their present ages are 16,28,36 years .

18.	My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was bom. If my sister was 4 years of age when my brother was born, then, what was the age of my father and mother respectively when my brother was born?
	A.  32 yrs, 23 yrs
	B.  32 yrs, 29 yrs
	C.  35 yrs, 29 yrs
	D.  35 yrs, 33 yrs

Solution

Clearly,my mother was born 3 years before I was born and 4 years after my sister was born. So, father's age when brother was born =(28+4) = 32 years. mother's age when brother was born =(26 - 3) = 23 years.