Arithmatical -Simplification
DIRECTIONS : Problems based on Simplification.
1. |
A classroom has equal number of boys and girls. Eight girls left to play kho-kho, leaving twice as many boys as girls in the classroom. What was the total number of girls and boys present initially? |
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A. 16 |
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B. 24 |
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C. 32 |
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D. 48 |
Solution |
Let the number of boys = x. |
Then, number of girls = x. |
Now, 2( x - 8) = x. |
x= 16. |
Total number of students = 2x = 2 x16 = 32. |
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2. |
N number of persons decided to raise Rs.3 lakhs by equal contribution from each. Had they contributed Rs.50 each extra, the contribution would have been Rs.3.25 lakhs. How many persons are there? |
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A. 400 |
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B. 500 |
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C. 550 |
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D. 600 |
Solution |
N X 50 | = (325000 - 300000) |
= 25000 |
N | = 25000 / 50 |
= 500. |
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3. |
In a classroom, if 6 students per bench are assigned to accommodate all students, one more bench will be required. However, if 7 students are accommodate per bench, there would be a space left for 5 students.What is the number of students in the class? |
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A. 30 |
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B. 45 |
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C. 42 |
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D. 72 |
Solution |
Let the number of benches in the class be x. |
Then, 6(x + 1) = 7x - 5 |
x = 11. |
Hence, number of students in the class | = 6 ( x + 1) |
= 6 x 12 |
= 72. |
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4. |
5.8 ×2.5 + 0.6 ×6.75 + 139.25= ? |
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A. 157.30 |
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B. 157.80 |
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C. 158.40 |
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D. 160.30 |
Solution |
Given exp. | = 14.5 + 4.05 + 139.25 |
‹=› 157.80. |
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5. |
On a sports day, if 30 children were made to stand in a column, then 16 columns could be formed. If 24 children were to stand in a column, then how many columns could be formed? |
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A. 20 |
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B. 22 |
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C. 29 |
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D. 452 |
Solution |
Total number of children | = (30 x 16) |
‹=› 480. |
Number of columns of 24 children each | = (480 /24) |
‹=›20. |
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