Arithmatical - Percentage
DIRECTIONS : Problems based on Percentage.
11. |
In an examination, 5% of the applicants were found ineligible and 85% of the eligible candidates belonged to the general category. If 4275 eligible candidates belonged to other categories, then how many candidates applied for the examination? |
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A. 30,000 |
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B. 35,000 |
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C. 37,000 |
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D. None of these |
Solution |
Let the number of applicants be x.Number of eligible candidates | = 95% of x. |
Eligible candidates of each other categories | = 15% of (95% of x). |
=(15/100×95/100×x) |
= 57/400×x. |
Therefore, 57/400×x | = 4275 |
‹=› x =(4275×400 / 57) |
‹=› 30000. |
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12. |
A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had |
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A. 588 apples |
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B. 600 apples |
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C. 672 apples |
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D. 700 apples |
Solution |
Suppose originally he had x apples. |
Then,(100-40)% of x = 420. |
‹=› 60/100×x = 420 |
x ‹=› (420 ×100 / 60 |
‹=› 700. |
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13. |
270 students appeared for an examination, of which 252 passed. The pass percentage is |
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A. 80% |
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B. 85%×1/2% |
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C. 90% |
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D. 93×1/3% |
Solution |
Pass percentage | = (252/270 ×100)% |
= 280/3% |
‹=› 93×1/3%. |
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14. |
Raman’s salary was decreased by 50% and subsequently increased by 50%. How much percent does he loss? |
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A. Rs.25 |
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B. Rs.50 |
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C. Rs.75 |
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D. Rs.85 |
Solution |
Let the origianl salary = Rs. 100. |
New final salary | ‹=› 150% of (50% of Rs. 100) |
‹=›Rs.(150/100×50/100×100) |
‹=› Rs. 75. |
Decrease = 25%. |
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15. |
How many litres of pure acid are there in 8 litres of a 20% solution? |
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A. 1.4 |
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B. 1.5 |
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C. 1.6 |
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D. 2.4 |
Solution |
Quantity of pure acid | = 20% of 8 litres |
= (20/100×8)litres |
= 1.6 litres. |
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