Arithmatical - Percentage
DIRECTIONS : Problems based on Percentage.
21. |
The price of a car is Rs. 3,25,000. It was insured to 85% of its price. The car was damaged completely in an accident and the insurance company paid 90% of the insurance. What was the difference between the price of the car and the amount received? |
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A. Rs.32.500 |
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B. Rs.48,750 |
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C. Rs.76,375 |
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D. Rs.81,250 |
Solution |
Amount paid to car owner | = 90% of 85% of Rs. 3,25,000. |
= Rs. (90/100 ×85/100 ×325000) |
= Rs. 2,48,625. |
Required differene | = Rs. (325000 - 248625) |
= Rs. 76,375. |
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22. |
What percent of a day is 3 hours? |
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A. 12×1/2% |
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B. 16×1/2% |
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C. 18×2/3% |
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D. 22×1/2% |
Solution |
Required percentage | = (3/24×100)% |
= (25 / 2)%. |
= 12×1/2%. |
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23. |
If number x is 10% less than another number y and y is 10% more than 125, then x is equal to |
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A. 123.75 |
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B. 140.55 |
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C. 143 |
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D. 150 |
Solution |
y = 125 + 10% of 125 | ‹=› 125 + 12.50 |
= 137.50. |
x = 137.50 - 10% of 137.50 | ‹=› 137.50 - 13.75 |
= 123.75. |
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24. |
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is |
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A. 4.37% |
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B. 5% |
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C. 6% |
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D. 8.75% |
Solution |
Increase in 10 years | = (262500 - 175000) |
= 87500. |
Increase% | = (87500/175000×100)% |
= 50%. |
Required average | = (50/10)% |
= 5%. |
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25. |
A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are |
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A. 300 |
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B. 500 |
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C. 800 |
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D. 1000 |
Solution |
Let their maximum marks be x. |
Then, 33% of x = 125 + 40 |
‹=› 33/100×x= 165 |
x‹=› (165×100/33) |
‹=› 500. |
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