Arithmatical - Percentage

DIRECTIONS : Problems based on Percentage.
21. The price of a car is Rs. 3,25,000. It was insured to 85% of its price. The car was damaged completely in an accident and the insurance company paid 90% of the insurance. What was the difference between the price of the car and the amount received?
  A.  Rs.32.500
  B.  Rs.48,750
  C.  Rs.76,375
  D.  Rs.81,250
Solution
Amount paid to car owner= 90% of 85% of Rs. 3,25,000.
= Rs. (90/100 ×85/100 ×325000)
= Rs. 2,48,625.
Required differene= Rs. (325000 - 248625)
= Rs. 76,375.
22. What percent of a day is 3 hours?
  A.  12×1/2%
  B.  16×1/2%
  C.  18×2/3%
  D.  22×1/2%
Solution
Required percentage= (3/24×100)%
= (25 / 2)%.
= 12×1/2%.

23. If number x is 10% less than another number y and y is 10% more than 125, then x is equal to
  A.  123.75
  B.  140.55
  C.  143
  D.  150
Solution
y = 125 + 10% of 125‹=› 125 + 12.50
= 137.50.
x = 137.50 - 10% of 137.50‹=› 137.50 - 13.75
= 123.75.
24. The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is
  A.  4.37%
  B.  5%
  C.  6%
  D.  8.75%
Solution
Increase in 10 years= (262500 - 175000)
= 87500.
Increase%= (87500/175000×100)%
= 50%.
Required average= (50/10)%
= 5%.
25. A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are
  A.  300
  B.  500
  C.  800
  D.  1000
Solution
Let their maximum marks be x.
Then, 33% of x = 125 + 40
‹=› 33/100×x= 165
x‹=› (165×100/33)
‹=› 500.
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