a2zinterviews

16.	Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get ?
	A.  45%
	B.  57%
	C.  60%
	D.  65%

Solution

Total number of votes polled = (1136 + 7636 + 11628 ) = 20400. Required percentage = (11628 / 20400 ×100)% = 57%.

17.	Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%. then what was the cost of the tax free items?
	A.  Rs.15
	B.  Rs.15.70
	C.  Rs.19.70
	D.  Rs.20

Solution

Let the amount of taxable purchases be Rs.x. Then, 6% of x = 30/100 x ‹=› (30/100×100/6) = 5. Cost of tax free items = Rs.[25 - (5 + 0.30)] = Rs. 19.70

18.	In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?
	A.  7600
	B.  8000
	C.  8400
	D.  Data inadequate

Solution

Let the number of candidates appeared from each state be x. Then, 7% of x - 6% of x = 80 ‹=›1% of x = 80 ‹=› x= 80 ×100 =8000.

19.	A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction?
	A.  8%
	B.  9%
	C.  10%
	D.  11%

Solution

Actual price = Rs. (25 + 2.50) = Rs. 27.50 Therefore, saving = (2.50 / 27.50 ×100)% = 100 / 11% = 9×1/11% = 9%.

20.	Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are
	A.  39, 30
	B.  41, 32
	C.  42, 33
	D.  43, 34

Solution

Let their marks be (x+9) and x. Then, x+9 = 56/100(x + 9 +x) ‹=› 25(x+9) ‹=› 14 (2x + 9) ‹=›3x = 99 ‹=›x = 33. SO, their marks are 42 and 33.