a2zinterviews

11.	The unit's digit in the product 274 × 318 × 577 × 313 is
	A.   2
	B.  3
	C.  4
	D.  5

Solution

Required digit = Unit digit in(4×8×7×3). = 2.

12.	The difference between the place values of 7 and 3 in the prime number 527435 is
	A.  4
	B.  5
	C.  45
	D.  6970

Solution

(place value of 7)-(place value of 3) = (7000 - 30) = 6970.

13.	If the largest three digit number is subtracted from the smallest five digit number, then the remainder is
	A.  1
	B.  9000
	C.  9001
	D.  90001

Solution

Required remainder = (10000 - 999) =9001

14.	5978 + 6134 + 7014
	A.  16226
	B.  19126
	C.  19216
	D.  19226

Solution

5978 + 6134 + 7014 = 19126.

15.	The digit in unit's place of the product (459 ×46×28×484) is 2, the digit in place of * is
	A.  3
	B.  5
	C.  7
	D.  9

Solution

(9×6×4) = 216. In order to obtain 2 at the unit place, we must multiply 216 by 2 or 7.