DIRECTIONS : Problems based on Numbers.
41. |
Of the three numbers, the sum of the first two is 45; the sum of the second and the third is 55 and the sum of the third and thrice the first is 90. The third number is |
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A. 10 |
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B. 20 |
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C. 30 |
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D. 40 |
Solution |
Let the number be x, y and Z. |
= Then, x+y=45, y+z=55&3x+z=90 |
‹=›y=45-x, z=55-y = 55-(45-x) = 10+x |
‹=›Therefore 3x+10+x = 90 or x = 20. |
y=(45-20)=25 and z=(10+20)= 30. |
Therefore Third number = 30. |
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42. |
Two different natural numbers are such that their product is less than their sum. One of the numbers must be |
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A. 1 |
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B. 2 |
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C. 3 |
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D. 4 |
Solution |
Since 1. x<1+x, so one of the numbers is 1. |
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43. |
In a two digit number, the digit in the units place is four times the digit in ten's place and sum of the digits is equal to 10. What is the number? |
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A. 25 |
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B. 28 |
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C. 32 |
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D. 36 |
Solution |
Let the ten digits be x. Then,units digit=4x |
Therefore x + 4x = 10 |
‹=›5x = 10 |
‹=›x= 2. |
So, ten's digit = 2, unit's digit = 8.
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Hence, the required number is 28. |
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44. |
The sum of the digits of a two digit number is 9 less than the number. Which of the following digits is at units place of the number? |
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A. 1 |
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B. 2 |
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C. 3 |
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D. Data inadequate |
Solution |
Let the ten's digit be x and unit's digit be y. Then, (10 x + y)-(x + y)=9 or x=1. |
From this data, we cannot find y, the units digit. So, the data is inadequate. |
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45. |
What is the sum of two consecutive even numbers, the difference of whose squares is 84? |
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A. 34 |
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B. 38 |
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C. 42 |
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D. 46 |
Solution |
Let the numbers be x and x + 2. |
Then, (x + 2)2–x2 = 84 |
‹=›4x + 4 = 84 |
‹=›4x = 80 |
‹=›x = 20. |
Required sum = x+(x+2)= 2x+2 = 42. |
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