Arithmatical - True Discount
DIRECTIONS : Problems based on True discounts.
6. |
The present worth of Rs. 2310 due 2 1/2 years hence, the rate of interest being 15% per annum, is |
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A. Rs.1680 |
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B. Rs.1750 |
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C. Rs.1840 |
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D. Rs.1443.75 |
Solution |
P.W.= Rs | = [100 x 2310/100 +(15 x5/2)] |
= Rs. 1680. |
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7. |
The true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160. The time after which it is due iss |
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A. 6 months |
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B. 8 months |
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C. 9 months |
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D. 10 months |
Solution |
P.W | = Rs. (1760 -160) |
= Rs.1600 |
S.I. on Rs. 1600 at 12% is Rs. 160. |
Time | = (100 x 160/1600 x 12) |
=5/6 years. |
=(5/6 x12) months |
=10 months. |
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8. |
Find the present worth of Rs. 930 due 3 years hence at 8% per annum. Also find the discount? |
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A. Rs.500 |
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B. Rs.625 |
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C. Rs. 750 |
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D. Rs. 890 |
Solution |
P.W | =100 x Amount/100+(RxT) |
= Rs[100x930/100+(8x3)] |
= Rs.(100x930/124) |
= Rs.750. |
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9. |
A man purchased a cow for Rs. 3000 and sold it the same day for Rs.3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of |
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A. 0% |
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B. 5% |
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C. 7.5% |
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D. 10% |
Solution |
C.P | = Rs. 3000. |
S.P | =Rs[3600x100/100+(10x2)] |
=3000 |
So, Gain is 0 %. |
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10. |
If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is |
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A. Rs.768 |
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B. Rs.968 |
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C. Rs.1960 |
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D. Rs.2400 |
Solution |
P.W | =100 x T.D/R x T |
= 100 x 168/14 x 2 |
= 600. |
Sum | = (P.W + T.D) |
Rs. (600 + 168) |
= Rs. 768. |
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