Arithmatical - True Discount
DIRECTIONS : Problems based on True discounts.
11. |
The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 80 respectively. The sum is |
|
A. Rs.1800 |
|
B. Rs.1450 |
|
C. Rs.1360 |
|
D. Rs.6800 |
Solution |
Sum | =S.I x T.D / S.I- T.D |
= (85x80 / 85–80) |
= Rs.1360. |
|
12. |
The true discount on a bill due 9 months hence at 12% per annum is Rs.540. Find the amount of the bill and its present worth. |
|
A. Rs.2500 |
|
B. Rs. 5000 |
|
C. Rs. 5500 |
|
D. Rs. 6000 |
Solution |
Let amount be Rs.X then, |
X×R×T/100+(R×T) | =T.D |
= X×12×3/4/100+(12×3/4) |
= 540 |
X=(540×109/9) |
= Rs. 6540 |
Amount | = Rs. 6540. |
P.W | = Rs.(6540 - 540) |
= Rs. 6000. |
|
13. |
The true discount on a bill due 9 months hence at 16% per annum is Rs.189. The amount of the bill is |
|
A. Rs.2268 |
|
B. Rs.1575 |
|
C. Rs.1764 |
|
D. Rs.1386 |
Solution |
Let P.W. be x. Then, S.I. on Rs. x at 16% for 9 months |
= Rs. 189 |
Therefore x×16×9 / 12 × 1 / 100 |
= 189 or x = 1575 |
P.W |
= Rs.1575 |
Sum due |
= P.W. + T.D. |
= Rs.(1575 + 189) |
= Rs.1764. |
|
14. |
A man wants to sell his scooter. There are two offers, one at Rs. 12,000 cash and the other at a credit of Rs.12,880 to be paid after 8 months, money being at 18% per annum. Which is the best offer? |
|
A. Rs.12,000 in cash |
|
B. Rs.12880 ar credit |
|
C. Both are equally good |
|
D. None of these |
Solution |
P.W. of Rs. 12880 due 8 months hence | = Rs. [12880×100 / 100 + (18 × 8 / 12)] |
= Rs. (12880×100 / 112) |
= Rs.11500 |
Clearly, Rs. 12000 in cash is a better offer. |
|