Arithmatical - True Discount
DIRECTIONS : Problems based on True discounts.
1. |
If Rs.10 be allowed as true discount on a bill of Rs.110 due at the end of a certain time, then the discount allowed on the same sum due at the end of double the time is |
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A. Rs.21.81 |
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B. Rs.18.33 |
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C. Rs.21 |
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D. Rs.22 |
Solution |
S.I on Rs.(110 - 10) for a certain time | = Rs.10. |
S.I on Rs. 100 double the time | = Rs.20. |
T.D on Rs.120 | = Rs.(120 - 100) |
= Rs.20. |
T.D on Rs.110 | = Rs.(20/120×110) |
= Rs.18.33. |
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2. |
A man buys a watch for Rs.1950 in cash and sells it for Rs.2200 at a credit of 1 year. If the rate of interests is 10% per annum, the man |
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A. Gain Rs.55 |
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B. Gain Rs.30 |
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C. Loses Rs.30 |
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D. Gains Rs.50 |
Solution |
S.P | =P.W. of Rs.2200 due 1 year |
= Rs.[2200×100/100+(10×1)] |
= Rs.2000. |
Gain | =Rs.(2000 - 1950) |
= Rs.50. |
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3. |
Rs.20 is the true discount on Rs.260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same? |
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A. Rs.10 |
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B. Rs.10.40 |
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C. Rs.15.20 |
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D. Rs.13 |
Solution |
S.I.on Rs.(260-20) for a given time | = Rs. 20 |
S.I. on Rs. 240 for half the time | = Rs. 10. |
T.D. on Rs. 250 | = Rs. 10. |
T.D. on Rs. 260 | = Rs.(10/250×260) |
= Rs. 10.40 |
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4. |
A trader owens a merchant Rs.10,028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest is 12% per annum, how much cash should he pay? |
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A. Rs.9025.20 |
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B. Rs.9200 |
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C. Rs.9600 |
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D. Rs.9560 |
Solution |
Required money = | P.W of Rs.10028 due 9 months |
Rs.[10028x100/100+(12x9/12)] |
= Rs.9200. |
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5. |
The true discount on Rs.2562 due 4 months hence is Rs.122. The rate percent is |
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A. 12 % |
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B. 13 % |
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C. 15 % |
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D. 14 % |
Solution |
P.W | = Rs.(2562 - 122) |
= Rs. 2440. |
S.I on Rs.2440 for 4 months is Rs.12 |
Rate | = (100 x 122/2440x1/3)% |
= 15%. |
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