Arithmatical - True Discount
DIRECTIONS : Problems based on True discounts.
15. |
The true discount on a certain sum of money due 3 years hence is Rs.250 and the simple interest on the same sum for the time and at the same rate is Rs.375. Find the sum? |
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A. Rs.500 |
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B. Rs.750 |
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C. Rs.1000 |
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D. Rs.1250 |
Solution |
T.D | = Rs.250 |
S.I | = Rs.375 |
Sum due | = S.I×T.D/(S.I)-(T.D) |
= Rs.(375×250/375-250 ) |
= Rs.750. |
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16. |
The interest on Rs.750 for 2 years is the same as the true discount on Rs.960 due 2 years hence. If the rate of interest is the same in both cases, it is |
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A. 10% |
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B. 12% |
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C. 14% |
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D. 18% |
Solution |
S.I. on Rs.750 | = T.D. on Rs.960 |
This means P.W. of Rs.960 due 2 years hence is Rs.750. |
Therefore T.D. | = Rs.(960 - 750) |
= Rs.210. |
Thus, S.I. on Rs.750 for 2 years is Rs.210 |
Rate | = Rs.(100 × 210 / 750 × 2)% |
= 14%. |
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